Timeline for Cauchy integral and residue theorem
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 8, 2019 at 13:31 | vote | accept | BeeTiau | ||
| Sep 8, 2019 at 11:17 | comment | added | user131781 | Very glad to have been of help—-best of luck for the future. | |
| Sep 8, 2019 at 11:12 | vote | accept | BeeTiau | ||
| Sep 8, 2019 at 11:12 | |||||
| Sep 8, 2019 at 11:02 | comment | added | BeeTiau | Thanks you! I really appreciate your suggestion and effort. Many people have now commented that this kind of question is not appropriate to be asked in here. I don't know why. While your response seems to be what I am looking for; a kind of direction from a math expert to someone who's completely clueless. I appreciate your effort! thanks! | |
| Sep 8, 2019 at 11:00 | comment | added | user131781 | You mean $|\zeta|$.This is simply the fact that a contour integral of an analytic function around the unit circle, say, is zero if the function is analytic in its interior. So the formulae will be different, depending on the position of $\zeta$ since the singularity of the integrand, i.e., the zero of the denominator, takes place at this point. I suggest you read an elementary introduction to complex variables, concentrating on the Cauchy integral formula. | |
| Sep 8, 2019 at 10:20 | comment | added | BeeTiau | Ah, this is it. If I may ask you a follow-up question. Why does $\zeta$ must be inside, i.e. $\zeta < 1$ for the first formulae to be correct? I really want to know the answer of this--Or, $\zeta > 1$ for the second formulae to be correct. | |
| Sep 8, 2019 at 6:12 | history | answered | user131781 | CC BY-SA 4.0 |