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Oct 20, 2019 at 1:07 vote accept Concu Bine
Sep 6, 2019 at 6:34 comment added Christian Clason Yes, strongly convex functions are in particular strictly convex, which is the property that guarantees the bijection (of the subgradient as a set-valued operator, which reduces to the gradient if you also have smoothness).
Sep 6, 2019 at 1:37 comment added Concu Bine Does the gradient remain a bijection? If not, what guarantees it?
Sep 5, 2019 at 11:03 history answered Christian Clason CC BY-SA 4.0