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Sep 6, 2019 at 14:01 vote accept Nicky
Sep 5, 2019 at 15:20 comment added Simon Henry $\pi_0$ (and $\pi_0^{\tau}$) commutes to colimits (it is a left adjoint), but not $\pi_n$.
Sep 5, 2019 at 15:18 answer added Simon Henry timeline score: 1
Sep 5, 2019 at 14:45 history edited Nicky CC BY-SA 4.0
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Sep 5, 2019 at 14:19 history edited Nicky CC BY-SA 4.0
added 305 characters in body
Sep 5, 2019 at 10:06 history asked Nicky CC BY-SA 4.0