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We heard and learned from Mike Miller's answer to Not all manifolds can be triangulated: In which dimensions? that "All orientable 5-dimensional manifolds are triangulable. In dimensions at least 6, though, you can use [Galewski and Stern's] construction to produce non-triangulable orientable manifolds."

What are some examples of non-triangulable manifolds that are orientable, and some examples that are non-orientable?

  • Orientability of non-triangulable manifolds, criteria and examples?

    Orientability of non-triangulable manifolds, criteria and examples?

     
  • Non-Orientability of non-triangulable manifolds, criteria and examples?

    Non-Orientability of non-triangulable manifolds, criteria and examples?


  • 4-dimensional $\mathrm E_8$-manifold is non-triangulable. But it is a spin manifold. Then, is $\mathrm E_8$-manifold orientable or not? Why and how to prove this?

It looks that the 4-dimensional topological spin cobordism gives rise to an integer $\mathbb{Z}$ classification. While the $\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification instead. In contrast, the 4-dimensional topological $\mathrm{pin}^+$ bordism gives rise to a $\mathbb{Z}/8\mathbb{Z} \oplus \mathbb{Z}/2\mathbb{Z}$ classification, and the 4-dimensional topological $\mathrm{pin}^-$ bordism gives rise to a $\mathbb{Z}/2\mathbb{Z}$ classification. In this sense, it looks that the $\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification of both topological non-orientable $\mathrm{pin}^+$ and $\mathrm{pin}^-$ bordism, but not the orientable topological spin bordism. Then, should $\mathrm E_8$-manifold be orientable or not?

We heard and learned from Mike Miller's answer to Not all manifolds can be triangulated: In which dimensions? that "All orientable 5-dimensional manifolds are triangulable. In dimensions at least 6, though, you can use [Galewski and Stern's] construction to produce non-triangulable orientable manifolds."

What are some examples of non-triangulable manifolds that are orientable, and some examples that are non-orientable?

  • Orientability of non-triangulable manifolds, criteria and examples?
     
  • Non-Orientability of non-triangulable manifolds, criteria and examples?

  • 4-dimensional $\mathrm E_8$-manifold is non-triangulable. But it is a spin manifold. Then, is $\mathrm E_8$-manifold orientable or not? Why and how to prove this?

It looks that the 4-dimensional topological spin cobordism gives rise to an integer $\mathbb{Z}$ classification. While the $\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification instead. In contrast, the 4-dimensional topological $\mathrm{pin}^+$ bordism gives rise to a $\mathbb{Z}/8\mathbb{Z} \oplus \mathbb{Z}/2\mathbb{Z}$ classification, and the 4-dimensional topological $\mathrm{pin}^-$ bordism gives rise to a $\mathbb{Z}/2\mathbb{Z}$ classification. In this sense, it looks that the $\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification of both topological non-orientable $\mathrm{pin}^+$ and $\mathrm{pin}^-$ bordism, but not the orientable topological spin bordism. Then, should $\mathrm E_8$-manifold be orientable or not?

We heard and learned from Mike Miller's answer to Not all manifolds can be triangulated: In which dimensions? that "All orientable 5-dimensional manifolds are triangulable. In dimensions at least 6, though, you can use [Galewski and Stern's] construction to produce non-triangulable orientable manifolds."

What are some examples of non-triangulable manifolds that are orientable, and some examples that are non-orientable?

  • Orientability of non-triangulable manifolds, criteria and examples?

  • Non-Orientability of non-triangulable manifolds, criteria and examples?


  • 4-dimensional $\mathrm E_8$-manifold is non-triangulable. But it is a spin manifold. Then, is $\mathrm E_8$-manifold orientable or not? Why and how to prove this?

It looks that the 4-dimensional topological spin cobordism gives rise to an integer $\mathbb{Z}$ classification. While the $\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification instead. In contrast, the 4-dimensional topological $\mathrm{pin}^+$ bordism gives rise to a $\mathbb{Z}/8\mathbb{Z} \oplus \mathbb{Z}/2\mathbb{Z}$ classification, and the 4-dimensional topological $\mathrm{pin}^-$ bordism gives rise to a $\mathbb{Z}/2\mathbb{Z}$ classification. In this sense, it looks that the $\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification of both topological non-orientable $\mathrm{pin}^+$ and $\mathrm{pin}^-$ bordism, but not the orientable topological spin bordism. Then, should $\mathrm E_8$-manifold be orientable or not?

'Oreintable', and some TeX fixes
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Non/Oreintability(Non-)Orientability of non-triangulable manifolds

We heard and learned from thatMike Miller's answer to Not all manifolds can be triangulated: In which dimensions?. that "All orientable 5-dimensional manifolds are triangulable. In dimensions at least 6, though, you can use their[Galewski and Stern's] construction to produce non-triangulable orientable manifolds."

What are some examples of non-triangulable manifolds whichthat are orientable, and some examples that are non-orientable?

  • OreintableOrientability of non-triangulable manifolds, criteria and examples?
  • Non-OreintableOrientability of non-triangulable manifolds, criteria and examples?

  • 4-dimensional E$_8$$\mathrm E_8$-manifold is non-triangulable. But it is a spin manifold. Then, is E$_8$$\mathrm E_8$-manifold oreintableorientable or not? Why and how to prove this?

It looks that the 4-dimensional topological spin cobordism gives rise to an integer $\mathbb{Z}$ classification. While the E$_8$$\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification instead. In contrast, the 4-dimensional topological pin$^+$$\mathrm{pin}^+$ bordism gives rise to a $\mathbb{Z}/8\mathbb{Z} \oplus \mathbb{Z}/2\mathbb{Z}$ classification, and the 4-dimensional topological pin$^-$$\mathrm{pin}^-$ bordism gives rise to a $\mathbb{Z}/2\mathbb{Z}$ classification. In this sense, it looks that the E$_8$$\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification of both topological non-orientable pin$^+$$\mathrm{pin}^+$ and pin$^-$$\mathrm{pin}^-$ bordism, but not the orientable topological spin bordism. Then, should E$_8$$\mathrm E_8$-manifold be orientable or not?

Non/Oreintability of non-triangulable manifolds

We heard and learned from that Not all manifolds can be triangulated: In which dimensions?. "All orientable 5-dimensional manifolds are triangulable. In dimensions at least 6, though, you can use their construction to produce non-triangulable orientable manifolds."

What are some examples of non-triangulable manifolds which are orientable and non-orientable?

  • Oreintable of non-triangulable manifolds, criteria and examples?
  • Non-Oreintable of non-triangulable manifolds, criteria and examples?

  • 4-dimensional E$_8$-manifold is non-triangulable. But it is a spin manifold. Then, is E$_8$-manifold oreintable or not? Why and how to prove this?

It looks that the 4-dimensional topological spin cobordism gives rise to an integer $\mathbb{Z}$ classification. While the E$_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification instead. In contrast, the 4-dimensional topological pin$^+$ bordism gives rise to a $\mathbb{Z}/8\mathbb{Z} \oplus \mathbb{Z}/2\mathbb{Z}$ classification, and the 4-dimensional topological pin$^-$ bordism gives rise to a $\mathbb{Z}/2\mathbb{Z}$ classification. In this sense, it looks that the E$_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification of both topological non-orientable pin$^+$ and pin$^-$ bordism, but not the orientable topological spin bordism. Then, should E$_8$-manifold be orientable or not?

(Non-)Orientability of non-triangulable manifolds

We heard and learned from Mike Miller's answer to Not all manifolds can be triangulated: In which dimensions? that "All orientable 5-dimensional manifolds are triangulable. In dimensions at least 6, though, you can use [Galewski and Stern's] construction to produce non-triangulable orientable manifolds."

What are some examples of non-triangulable manifolds that are orientable, and some examples that are non-orientable?

  • Orientability of non-triangulable manifolds, criteria and examples?
  • Non-Orientability of non-triangulable manifolds, criteria and examples?

  • 4-dimensional $\mathrm E_8$-manifold is non-triangulable. But it is a spin manifold. Then, is $\mathrm E_8$-manifold orientable or not? Why and how to prove this?

It looks that the 4-dimensional topological spin cobordism gives rise to an integer $\mathbb{Z}$ classification. While the $\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification instead. In contrast, the 4-dimensional topological $\mathrm{pin}^+$ bordism gives rise to a $\mathbb{Z}/8\mathbb{Z} \oplus \mathbb{Z}/2\mathbb{Z}$ classification, and the 4-dimensional topological $\mathrm{pin}^-$ bordism gives rise to a $\mathbb{Z}/2\mathbb{Z}$ classification. In this sense, it looks that the $\mathrm E_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification of both topological non-orientable $\mathrm{pin}^+$ and $\mathrm{pin}^-$ bordism, but not the orientable topological spin bordism. Then, should $\mathrm E_8$-manifold be orientable or not?

added 3 characters in body
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We heard and learned from that Not all manifolds can be triangulated: In which dimensions?. "All orientable 5-dimensional manifolds are triangulable. In dimensions at least 6, though, you can use their construction to produce non-triangulable orientable manifolds."

What are some examples of non-triangulable manifolds which are orientable and non-orientable?

  • Oreintable of non-triangulable manifolds, criteria and examples?
  • Non-Oreintable of non-triangulable manifolds, criteria and examples?

  • 4-dimensional E$_8$-manifold is non-triangulable. But it is a spin manifold. Then, is E$_8$-manifold oreintable or not? Why and how to prove this?

It looks that the 4-dimensional topological spin cobordism gives rise to an integer $\mathbb{Z}$ classification. While the E$_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification instead. In contrast, the 4-dimensional topological pin$^+$ bordism gives rise to a $\mathbb{Z}/8\mathbb{Z} \oplus \mathbb{Z}/2\mathbb{Z}$ classification, and the 4-dimensional topological pin$^-$ bordism gives rise to a $\mathbb{Z}/2\mathbb{Z}$ classification. In this sense, it looks that the E$_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification of both topological non-orientable pin$^+$ and pin$^-$ bordism, but not the orientable topological spin bordism. Then, should E$_8$-manifold be not orientable or not?

We heard and learned from that Not all manifolds can be triangulated: In which dimensions?. "All orientable 5-dimensional manifolds are triangulable. In dimensions at least 6, though, you can use their construction to produce non-triangulable orientable manifolds."

What are some examples of non-triangulable manifolds which are orientable and non-orientable?

  • Oreintable of non-triangulable manifolds, criteria and examples?
  • Non-Oreintable of non-triangulable manifolds, criteria and examples?

  • 4-dimensional E$_8$-manifold is non-triangulable. But it is a spin manifold. Then, is E$_8$-manifold oreintable or not? Why and how to prove this?

It looks that the 4-dimensional topological spin cobordism gives rise to an integer $\mathbb{Z}$ classification. While the E$_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification instead. In contrast, the 4-dimensional topological pin$^+$ bordism gives rise to a $\mathbb{Z}/8\mathbb{Z} \oplus \mathbb{Z}/2\mathbb{Z}$ classification, and the 4-dimensional topological pin$^-$ bordism gives rise to a $\mathbb{Z}/2\mathbb{Z}$ classification. In this sense, it looks that the E$_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification of both topological non-orientable pin$^+$ and pin$^-$ bordism, but not the orientable topological spin bordism. Then, should E$_8$-manifold be not orientable?

We heard and learned from that Not all manifolds can be triangulated: In which dimensions?. "All orientable 5-dimensional manifolds are triangulable. In dimensions at least 6, though, you can use their construction to produce non-triangulable orientable manifolds."

What are some examples of non-triangulable manifolds which are orientable and non-orientable?

  • Oreintable of non-triangulable manifolds, criteria and examples?
  • Non-Oreintable of non-triangulable manifolds, criteria and examples?

  • 4-dimensional E$_8$-manifold is non-triangulable. But it is a spin manifold. Then, is E$_8$-manifold oreintable or not? Why and how to prove this?

It looks that the 4-dimensional topological spin cobordism gives rise to an integer $\mathbb{Z}$ classification. While the E$_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification instead. In contrast, the 4-dimensional topological pin$^+$ bordism gives rise to a $\mathbb{Z}/8\mathbb{Z} \oplus \mathbb{Z}/2\mathbb{Z}$ classification, and the 4-dimensional topological pin$^-$ bordism gives rise to a $\mathbb{Z}/2\mathbb{Z}$ classification. In this sense, it looks that the E$_8$-manifold should be a manifold generator of the $\mathbb{Z}/2\mathbb{Z}$ classification of both topological non-orientable pin$^+$ and pin$^-$ bordism, but not the orientable topological spin bordism. Then, should E$_8$-manifold be orientable or not?

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