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Oct 17, 2021 at 23:26 history edited LSpice CC BY-SA 4.0
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Aug 7, 2010 at 18:56 comment added Daniel Asimov It's also amusing that given n, the complement of any countable dense subset of R^n is homeomorphic to the complement of any other such.
Aug 1, 2010 at 9:09 comment added Henno Brandsma It's more for those who want pure topological properties. Metrisable refers to an external object R, and some like this less as a property. I don't really care either way, now that we have a complete characterisation of metrisability since the fifties.
Jul 31, 2010 at 8:45 comment added Pete L. Clark I guess your comment about replacing metrizable by regular (Hausdorff) second countable is just for those who don't know Urysohn's Metrization Theorem?
Jul 31, 2010 at 8:44 comment added Pete L. Clark Neat. In particular, for any $p$, the rationals endowed with the $p$-adic metric are homeomorphic to the rationals endowed with the Euclidean metric. (This came up in an offhand way in an answer I gave here some months ago. In a comment, I sketched an argument that is certainly more complicated than this.)
Jul 31, 2010 at 6:17 history answered Henno Brandsma CC BY-SA 2.5