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Aug 24, 2019 at 13:56 comment added LSpice I agree with your correction; thanks. Actually it's a good thing, since the version without conjugation would have been holomorphic, hence contradicted @abx's nice answer.
Aug 24, 2019 at 13:54 history edited LSpice CC BY-SA 4.0
Edited to reflect @AliTaghavi's correction
Aug 24, 2019 at 5:00 comment added Ali Taghavi I unaccept the answer since you asked me so. but i still believe it can be revised .
Aug 24, 2019 at 4:47 comment added Ali Taghavi I do not see why it is wrong. Every fixed point free map $f$ works. you can revise it. i think we need conjugation too $\bar{b}, -\bar{a},\bar{d}, -\bar{c}$. Yes?any way your effort really helped me. Am I mistaken to think that your $f$ can be revised?any way should I un-accept(after all)?
Aug 24, 2019 at 3:20 comment added LSpice @AliTaghavi, this answer is wrong (sorry!). Please un-accept it so that I can delete it.
Aug 24, 2019 at 3:20 comment added Ali Taghavi Very interesting!what about the opposit direction?
Aug 24, 2019 at 3:19 history edited LSpice CC BY-SA 4.0
This answer is wrong
Aug 24, 2019 at 3:17 vote accept Ali Taghavi
Aug 24, 2019 at 4:49
Aug 24, 2019 at 3:13 history answered LSpice CC BY-SA 4.0