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Feb 13, 2020 at 17:00 comment added VS. mathworld.wolfram.com/LevyConstant.html
Aug 23, 2019 at 20:17 comment added Will Sawin As far as I can tell, you are correct and the other answers are irrelevant. This sort of regrouping is equivalent to writing $\zeta(2) = \sum_{n=1}^{\infty} \frac{1}{(2n-1)^2} + \frac{1} {(2n)^2}$ and is completely harmless, if one doesn't make an algebra error.
Aug 23, 2019 at 19:48 history answered Harry Richman CC BY-SA 4.0