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Timeline for Quantum inspired matrix inequality

Current License: CC BY-SA 4.0

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Aug 22, 2019 at 13:32 comment added Taylor Huang No, the argument does not hold. even if the triple sum contains all terms $(A_{ji}x_i)$, it does the square of not necessarily be greater. Since extra terms might cancel out with original terms.
Aug 22, 2019 at 11:35 history edited dioniz CC BY-SA 4.0
Corrected the expansion of the norm.
Aug 22, 2019 at 11:33 comment added dioniz You are right, but as far as I see the same argument still holds.
Aug 22, 2019 at 11:22 comment added Taylor Huang The first equation is in general wrong since it should be $$ \sup_{\Vert x\Vert=1}\sum_{j=1}^m\left|\sum_{i=1}^na_{ji}x_i\right|^2 $$
Aug 22, 2019 at 11:10 review First posts
Aug 22, 2019 at 12:11
Aug 22, 2019 at 11:05 history answered dioniz CC BY-SA 4.0