Timeline for Quantum inspired matrix inequality
Current License: CC BY-SA 4.0
6 events
when toggle format | what | by | license | comment | |
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Aug 22, 2019 at 13:32 | comment | added | Taylor Huang | No, the argument does not hold. even if the triple sum contains all terms $(A_{ji}x_i)$, it does the square of not necessarily be greater. Since extra terms might cancel out with original terms. | |
Aug 22, 2019 at 11:35 | history | edited | dioniz | CC BY-SA 4.0 |
Corrected the expansion of the norm.
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Aug 22, 2019 at 11:33 | comment | added | dioniz | You are right, but as far as I see the same argument still holds. | |
Aug 22, 2019 at 11:22 | comment | added | Taylor Huang | The first equation is in general wrong since it should be $$ \sup_{\Vert x\Vert=1}\sum_{j=1}^m\left|\sum_{i=1}^na_{ji}x_i\right|^2 $$ | |
Aug 22, 2019 at 11:10 | review | First posts | |||
Aug 22, 2019 at 12:11 | |||||
Aug 22, 2019 at 11:05 | history | answered | dioniz | CC BY-SA 4.0 |