Timeline for Finite field special functions
Current License: CC BY-SA 4.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 28, 2019 at 9:32 | comment | added | user144684 | Actually (0) (13) (26) (45) is exponential with multiplier 2 I checked | |
| Aug 27, 2019 at 21:26 | comment | added | Peter Taylor | @user144684, I'm not sure what misfire of the brain caused me to see that as an exponential relationship. Trying to find the appropriate term to correct it to. | |
| Aug 27, 2019 at 11:26 | comment | added | user144684 | I am trying to understand why (0) (13) (26) (45) is exponential. which multiplier works here ? | |
| Aug 26, 2019 at 21:08 | comment | added | user144684 | Running 37 minutes GF(31) - 0 results for now | |
| Aug 26, 2019 at 20:46 | comment | added | Peter Taylor | @user144684, that's $f(0), f(1), f(2), \ldots, f(6)$. | |
| Aug 26, 2019 at 20:15 | comment | added | user144684 | I see the following output for GF(7): 0, 3, 6, 1, 5, 4, 2 It is either by bug or I can't read this line | |
| Aug 26, 2019 at 18:53 | comment | added | user144684 | Thanks a lot !!! | |
| Aug 26, 2019 at 10:54 | comment | added | Peter Taylor | gist.github.com/pjt33/42a3bd6eaae04b8f74163825021a9d03 | |
| Aug 25, 2019 at 14:38 | comment | added | user144684 | Can ask you to shared your search algorithm in some programming language ? | |
| Aug 22, 2019 at 16:32 | comment | added | user144684 | Amazing result !! | |
| Aug 22, 2019 at 15:08 | history | edited | Peter Taylor | CC BY-SA 4.0 |
added 11904 characters in body
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| Aug 22, 2019 at 10:33 | comment | added | user144684 | Little note: all of such functions produces starter. I'd give the name for such starter. | |
| Aug 22, 2019 at 10:29 | comment | added | Peter Taylor | Hmm. These examples are all exponential (specifically, $f(2x) = 2f(x)$). I should be able to enumerate exponential functions much more efficiently, so I can check whether this class extends to $GF(127)$... | |
| Aug 22, 2019 at 10:15 | comment | added | Peter Taylor | Incidentally, since there's no use of multiplication in the definition of these functions, it just occurred to me to try searching for suitable functions over $Z_{15}$, and there is one pair, with representative $0(1,4)(2,8)(3,14)(5,10)(6,13)(7,9)(11,12)$. | |
| Aug 22, 2019 at 9:54 | comment | added | user144684 | Good idea to use algorithmic approach, great results !!! I tried to find using mathematical abstractions. | |
| Aug 22, 2019 at 9:00 | history | answered | Peter Taylor | CC BY-SA 4.0 |