Timeline for When is being flat a derived invariant?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Aug 21, 2019 at 8:52 | comment | added | Jeremy Rickard | Not a complete answer, but one necessary condition, which rules out many popular commutative rings, is that $k$ should have no finitely generated module $M$ with flat dimension equal to one. | |
| Aug 20, 2019 at 20:27 | history | edited | Mare | CC BY-SA 4.0 |
added 204 characters in body
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| Aug 20, 2019 at 20:20 | history | edited | Mare | CC BY-SA 4.0 |
edited title
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| Aug 20, 2019 at 14:54 | history | asked | Mare | CC BY-SA 4.0 |