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Dec 26, 2023 at 21:23 comment added Pietro Majer The contractibility of GL(H), looking closely to the construction, is due to the fact that in an infinite dimensional Hilbert space there is "enough room" to perform the maneuver, just like in the Hilbert Hotel there are enough rooms to host a new guest
Sep 17, 2019 at 16:44 comment added Ben Wieland My vague memory is that this information is better organized in terms of Grassmannians than groups, but I don't have anything specific to say.
Aug 17, 2019 at 20:16 comment added mme I guess I would say: $\Phi(V)$ is completely unconstrained when $V$ is finite-dimensional, while it is constrained by finite-dimensionality once you reach infinite dimensions, and the interesting topology accounts for how kernel and cokernel move around inside an infinite-dimensional space. On the other hand, when $V$ is infinite-dimensional the space $GL(V)$ is unconstrained because of the existence of a swindle.
Aug 16, 2019 at 15:01 history edited Thomas Rot CC BY-SA 4.0
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Aug 16, 2019 at 14:50 history edited Thomas Rot CC BY-SA 4.0
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Aug 16, 2019 at 14:48 history undeleted Thomas Rot
Aug 16, 2019 at 13:00 history deleted Thomas Rot via Vote
Aug 16, 2019 at 9:29 history asked Thomas Rot CC BY-SA 4.0