Timeline for Regular subsets of $\text{PSL}(2, q)$
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 7, 2021 at 9:23 | answer | added | Sean Eberhard | timeline score: 4 | |
| Aug 17, 2019 at 19:29 | comment | added | Richard Lyons | @StevenStadnicki Sorry, I read your question carelessly. | |
| Aug 17, 2019 at 11:04 | answer | added | Fedor Petrov | timeline score: 4 | |
| Aug 17, 2019 at 8:47 | vote | accept | Sean Eberhard | ||
| Aug 16, 2019 at 16:33 | answer | added | Peter Mueller | timeline score: 4 | |
| Aug 16, 2019 at 14:25 | comment | added | Steven Stadnicki | @RichardLyonsThe cosets are what I meant by 'inducing' a regular subgroup, though I should perhaps have phrased it the other way around. I really like the $A_6$ example, though; that's very helpful to me. Thank you! | |
| Aug 16, 2019 at 9:54 | comment | added | Fedor Petrov | I wonder whether it is realted to orthogonal Latin squares of size $q+1=4k+2$ which were assumed by Euler to not exist (disproved by R.C. Bose, S.S. Shrikhande and E.T. Parker). | |
| Aug 16, 2019 at 6:38 | comment | added | Sean Eberhard | @StevenStadnicki For $S_n$ and its standard action, regular subsets correspond exactly with $n\times n$ Latin squares, and there are many more of these than subgroups. In particular $A_6$ has no regular subgroup but it does have a regular subset (you need a $6\times 6$ Latin square with all rows even). | |
| Aug 15, 2019 at 22:10 | comment | added | Richard Lyons | Any coset of a regular subgroup is a regular subset. | |
| Aug 15, 2019 at 19:08 | comment | added | Steven Stadnicki | Can you give an example of a regular subset that doesn't induce a regular subgroup? | |
| Aug 15, 2019 at 9:26 | history | asked | Sean Eberhard | CC BY-SA 4.0 |