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Aug 14, 2019 at 20:46 comment added Pietro Majer Since g is known on [1/2,α], we can determine f(α/3) putting x=1/2 in the functional equation. But then, which other values can be found? Putting x=α/3 again we may find f(α/(3+α)), unless α<√(3/2), which is not excluded. In any case, I don't see how f(x) can possibly be determined for x< α-1...
Aug 14, 2019 at 19:55 comment added Carlo Beenakker just an observation: taking derivatives and then sending $x\rightarrow 0$ I find $f^{(n)}(0)=\alpha^n f^{(n)}(0)$, hence $f^{(n)}(0)=0$ for any $n\geq 1$.
Aug 14, 2019 at 12:51 history asked guigux CC BY-SA 4.0