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Aug 13, 2019 at 15:00 comment added M. Winter @Turbo Wait, are you asking about the rank of the adjacency matrix or the rank of $M$?
Aug 13, 2019 at 14:52 comment added Turbo @M.Winter Don't know since we round.
Aug 13, 2019 at 14:36 comment added M. Winter Shouldn't the rank of $M$ simply be $d$ (in $\Bbb R$ and $\Bbb F_2$), as the matrix contains the $d\times d$-identitiy matrix as a submatrix?
Aug 13, 2019 at 14:06 answer added M. Winter timeline score: 2
Aug 13, 2019 at 14:06 comment added Turbo True $n = 2^{d}$.
Aug 13, 2019 at 14:05 comment added Fedor Petrov $n=2^d$, right?
Aug 13, 2019 at 13:51 history asked Turbo CC BY-SA 4.0