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Aug 13, 2019 at 13:12 comment added Display name @GerryMyerson Yes. That and the prime generating example involving Wilson's Theorem was why I didn't allow floors or division.
Aug 13, 2019 at 13:11 comment added Robert Israel If you allow square roots and division when the results are integers, you can map those "infinitely many negative numbers" to $0$, since $(x + \sqrt{x^2})/2 = 0$ if $x \le 0$, $x$ if $x \ge 0$.
Aug 13, 2019 at 13:11 comment added Wojowu I have taken a liberty of changing the title to something more descriptive. Regarding the conjectures themselves, I have little hope for them being even remotely approachable. Even with Fermat numbers $2^{2^n}+1$, it has not been excluded that all but finitely many of them are primes.
Aug 13, 2019 at 13:09 history edited Wojowu CC BY-SA 4.0
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Aug 13, 2019 at 13:07 comment added Gerry Myerson Do you know about Mills' constant? en.wikipedia.org/wiki/Mills%27_constant
S Aug 13, 2019 at 11:28 history suggested Ali Taghavi CC BY-SA 4.0
I add a tag.
Aug 13, 2019 at 11:24 review Suggested edits
S Aug 13, 2019 at 11:28
Aug 13, 2019 at 10:53 history edited Display name CC BY-SA 4.0
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Aug 13, 2019 at 10:40 review First posts
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Aug 13, 2019 at 10:37 history asked Display name CC BY-SA 4.0