Timeline for Integral of Schur functions over $SU(N)$ instead of $U(N)$
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 9, 2019 at 17:24 | vote | accept | thedude | ||
| Aug 9, 2019 at 8:15 | answer | added | Carlo Beenakker | timeline score: 6 | |
| Aug 8, 2019 at 21:38 | comment | added | Dima Pasechnik | At least for $N=2$ it's explictly known how a $U(N)$ irreducible repsentation reduces upon restricting to $SU(N)$ (see e.g. here math.stackexchange.com/questions/2284576/…); the integral counts the number of irreducibles, if I'm not led astray by analogy with finite groups... | |
| Aug 8, 2019 at 18:57 | comment | added | thedude | @CarloBeenakker Why should it be the same? (I don't think they are the same) | |
| Aug 8, 2019 at 18:55 | comment | added | Carlo Beenakker | isn't the answer the same for $U(N)$ and $SU(N)$? | |
| Aug 8, 2019 at 18:09 | history | asked | thedude | CC BY-SA 4.0 |