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Aug 7, 2019 at 16:17 comment added mike Got it! Thanks again!
Aug 7, 2019 at 16:10 comment added GH from MO @mike: $\chi(17-k)=\chi(-k)=\chi(-1)\chi(k)=-\chi(k)$.
Aug 7, 2019 at 15:17 comment added mike Thanks a lot for the detailed answer! I noticed that you used $\chi(k)=-\chi(17-k)$. What is this (anti)symmetry? Best
Aug 7, 2019 at 14:07 vote accept mike
Aug 7, 2019 at 9:31 history edited GH from MO CC BY-SA 4.0
deleted 17 characters in body
Aug 7, 2019 at 8:40 history edited GH from MO CC BY-SA 4.0
added 2 characters in body
Aug 7, 2019 at 8:33 history edited David Loeffler CC BY-SA 4.0
missing i
Aug 7, 2019 at 8:32 history answered GH from MO CC BY-SA 4.0