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Aug 4, 2019 at 8:05 vote accept Chain Markov
Aug 4, 2019 at 6:05 comment added Derek Holt Yes sorry it was too late!
Aug 4, 2019 at 2:16 answer added Z3T3t3pON7 timeline score: 12
Aug 3, 2019 at 22:32 history edited YCor CC BY-SA 4.0
edited tags; edited title
Aug 3, 2019 at 20:33 comment added verret @IgorRivin It would follow from that statement, but that statement is not known.
Aug 3, 2019 at 20:28 comment added Igor Rivin Does this not follow from the fact that almost all groups of order bounded by $n$ are $2$-groups?
Aug 3, 2019 at 15:40 comment added Noah Snyder Do I remember right that the conjecture you mention is equivalent to the same conjecture but with "p-group of order less than n" in the numerator? If so, that seems discouraging because 2-generated is a powerful condition if you already know the group is a p-group (Burnside basis theorem, etc.), but seems pretty useless for groups that aren't p-groups.
Aug 3, 2019 at 15:27 history asked Chain Markov CC BY-SA 4.0