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Timeline for Greatest element of ${}^IW$

Current License: CC BY-SA 4.0

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Aug 6, 2019 at 20:55 comment added Hugh Thomas Nothing in your proof says that the map to the interval is surjective, and in fact it is not.
Aug 5, 2019 at 7:15 comment added James Cheung But it seems my proof works. Where does I get wrong?
Aug 3, 2019 at 18:46 comment added Hugh Thomas For the symmetric group on three letters, with simple roots $\alpha_1,\alpha_2$ and $I=\{\alpha_1\}$, we have that $^IW$ is not an interval in Bruhat order.
Aug 3, 2019 at 3:38 history answered James Cheung CC BY-SA 4.0