Skip to main content
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
added 23 characters in body
Source Link
James Baxter
  • 2.1k
  • 9
  • 25

Let $X$ be a continuous stochastic process with a.s. continuous sample paths on $[0, 1]$ such that $\mathbb E [X_t]$ is finite for all $t \in [0, 1]$. Given any non null subset $Y$ of the probability space, define $\mathbb Q_Y$ to be the restricted probability measure $\mathbb Q_Y [E] = P(E \cap Y)/P(Y)$.

Does it follow there exists some non null $Y$ such that that the function $f: [0, 1] \to R$ defined $f(t)$ $=$ $\mathbb E_{Q_Y} [X_t]$ is continuous a.e.?

Let $X$ be a continuous stochastic process on $[0, 1]$ such that $\mathbb E [X_t]$ is finite for all $t \in [0, 1]$. Given any non null subset $Y$ of the probability space, define $\mathbb Q_Y$ to be the restricted probability measure $\mathbb Q_Y [E] = P(E \cap Y)/P(Y)$.

Does it follow there exists some non null $Y$ such that that the function $f: [0, 1] \to R$ defined $f(t)$ $=$ $\mathbb E_{Q_Y} [X_t]$ is continuous a.e.?

Let $X$ be a stochastic process with a.s. continuous sample paths on $[0, 1]$ such that $\mathbb E [X_t]$ is finite for all $t \in [0, 1]$. Given any non null subset $Y$ of the probability space, define $\mathbb Q_Y$ to be the restricted probability measure $\mathbb Q_Y [E] = P(E \cap Y)/P(Y)$.

Does it follow there exists some non null $Y$ such that that the function $f: [0, 1] \to R$ defined $f(t)$ $=$ $\mathbb E_{Q_Y} [X_t]$ is continuous a.e.?

edited body
Source Link
James Baxter
  • 2.1k
  • 9
  • 25

Let $X$ be a continuous stochastic process on $[0, 1]$ such that $\mathbb E [X_t]$ is finite for all $t \in [0, 1]$. Given any non null subset $Y$ of the probability space, define $\mathbb Q_Y$ to be the restricted probability measure $\mathbb Q_Y [E] = P(E \cap Y)/P(Y)$.

Does it follow there exists some non null $Y$ such that that the function $f: [0, 1) \to R$$f: [0, 1] \to R$ defined $f(t)$ $=$ $\mathbb E_{Q_Y} [X_t]$ is continuous a.e.?

Let $X$ be a continuous stochastic process on $[0, 1]$ such that $\mathbb E [X_t]$ is finite for all $t \in [0, 1]$. Given any non null subset $Y$ of the probability space, define $\mathbb Q_Y$ to be the restricted probability measure $\mathbb Q_Y [E] = P(E \cap Y)/P(Y)$.

Does it follow there exists some non null $Y$ such that that the function $f: [0, 1) \to R$ defined $f(t)$ $=$ $\mathbb E_{Q_Y} [X_t]$ is continuous a.e.?

Let $X$ be a continuous stochastic process on $[0, 1]$ such that $\mathbb E [X_t]$ is finite for all $t \in [0, 1]$. Given any non null subset $Y$ of the probability space, define $\mathbb Q_Y$ to be the restricted probability measure $\mathbb Q_Y [E] = P(E \cap Y)/P(Y)$.

Does it follow there exists some non null $Y$ such that that the function $f: [0, 1] \to R$ defined $f(t)$ $=$ $\mathbb E_{Q_Y} [X_t]$ is continuous a.e.?

Source Link
James Baxter
  • 2.1k
  • 9
  • 25

Stochastic processes and continuity of expectation

Let $X$ be a continuous stochastic process on $[0, 1]$ such that $\mathbb E [X_t]$ is finite for all $t \in [0, 1]$. Given any non null subset $Y$ of the probability space, define $\mathbb Q_Y$ to be the restricted probability measure $\mathbb Q_Y [E] = P(E \cap Y)/P(Y)$.

Does it follow there exists some non null $Y$ such that that the function $f: [0, 1) \to R$ defined $f(t)$ $=$ $\mathbb E_{Q_Y} [X_t]$ is continuous a.e.?