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Bumped by Community user
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Anton Petrunin
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fixed English, formatting
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YCor
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A locally CAT(0)-metric metric on length space means that every point in it has a geodesically convex neighborhood such that every triangle in it is slimmer than the comparison triangle in the Euclidean plane. For example, the Riemannian metric with nonpositive sectional curvature is a locally CAT(0)-metric metric.

Let $M$ be a closed manifold and $M\times S^1$ admits locally CAT(0)-metrics, if $M$ also admits locally CAT(0)-metric?

Let $M$ be a closed manifold such that $M\times S^1$ admits a locally CAT(0) metric. Does $M$ also admit a locally CAT(0) metric?

A locally CAT(0)-metric on length space means that every point in it has a geodesically convex neighborhood such that every triangle in it is slimmer than the comparison triangle in the Euclidean plane. For example, the Riemannian metric with nonpositive sectional curvature is a locally CAT(0)-metric.

Let $M$ be a closed manifold and $M\times S^1$ admits locally CAT(0)-metrics, if $M$ also admits locally CAT(0)-metric?

A locally CAT(0) metric on length space means that every point in it has a geodesically convex neighborhood such that every triangle in it is slimmer than the comparison triangle in the Euclidean plane. For example, the Riemannian metric with nonpositive sectional curvature is a locally CAT(0) metric.

Let $M$ be a closed manifold such that $M\times S^1$ admits a locally CAT(0) metric. Does $M$ also admit a locally CAT(0) metric?

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Jialong Deng
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If M times circle admits a locally CAT(0)-metric, then M also carries a locally CAT(0)-metric?

A locally CAT(0)-metric on length space means that every point in it has a geodesically convex neighborhood such that every triangle in it is slimmer than the comparison triangle in the Euclidean plane. For example, the Riemannian metric with nonpositive sectional curvature is a locally CAT(0)-metric.

Let $M$ be a closed manifold and $M\times S^1$ admits locally CAT(0)-metrics, if $M$ also admits locally CAT(0)-metric?