Skip to main content
26 events
when toggle format what by license comment
Aug 24, 2019 at 16:36 comment added Paul B. Slater Thanks for the comment--will consider what you suggest!
Aug 24, 2019 at 12:57 comment added J. E. Pascoe @PaulB.Slater, it might be useful to consider the fact that operator monotone functions are exactly self maps of the upper half plane, and therefore have nice integral representations. In Peter Lax "Functional Analysis" book, I think these are called "Nevanlinna representations." To make a long story short, this would make your function $f$ depend on a real number $a,$ a nonnegative $b$ and a positive measure on the real line $\mu.$
Aug 21, 2019 at 0:33 comment added Paul B. Slater Thanks for the question J. E. Pascoe! I was conceiving of a (I guess) "functional" that would map the operator monotone functions into the values (25/341,...) of the "separability probabilities"--that is the ratio of the volume of the separable "two-qubit" states to the total (separable and entangled) states. In this conception, the states would be endowed with the metric corresponding (by the work of Petz-Sudar in J. Math. Phys.) to the specific operator monotone function. Happy to try to clarify further. But probably a "very tall order" for a "functional" to fulfill. "Pie-in-the-sky"?
Aug 20, 2019 at 15:27 comment added J. E. Pascoe @PaulB.Slater, what was the goal here? That is, the original question.
Jul 30, 2019 at 11:34 comment added Paul B. Slater J. E. Pascoe--I guess I didn't answer your question. $\log{t}$ clearly doesn't fit the titular relation employed by Denes Petz in his several papers pertaining to the matter. I'll have to re-examine them somewhat more closely, to see the origin of this specific definition.
Jul 29, 2019 at 15:11 comment added Paul B. Slater J. E. Pascoe--if $t>0$ and $g(t)=\frac{(t-1)}{\log{t}}$, then $g(t)=t g(t^{-1})$, as per the operator monotone relation indicated in the title.
Jul 29, 2019 at 13:23 comment added J. E. Pascoe Isn't $\log t$ operator monotone? That doesn't seem to satisfy that relation on $g$.
Jul 29, 2019 at 12:58 answer added Paul B. Slater timeline score: 0
Jul 28, 2019 at 20:25 comment added Paul B. Slater Well, the class of operator monotone functions is nondenumerably infinite--and I know at most three function values exactly. I was thinking of a function that would be able to give the values/probabilities for any member of the class.
Jul 28, 2019 at 19:59 comment added მამუკა ჯიბლაძე Is it acceptable, for example, to declare those values of $f$ that you want to be as you want and declare all other values of $f$ to be zero?
Jul 28, 2019 at 18:22 history edited Paul B. Slater CC BY-SA 4.0
modified title
Jul 28, 2019 at 18:01 history edited Paul B. Slater CC BY-SA 4.0
deleted 10 characters in body; edited title
Jul 28, 2019 at 17:47 history edited Paul B. Slater CC BY-SA 4.0
some rewriting
Jul 28, 2019 at 17:42 history edited Paul B. Slater CC BY-SA 4.0
added 1 character in body
Jul 28, 2019 at 17:29 comment added Paul B. Slater Thanks, Pietro Majer! Well, certaintly the domain is the set of operator monotone functions--that is those for which $g(t)=t g(t^{-1})$--and the range is $[0,\frac{25}{341}]$. Otherwise, I certainly don't have definite specifications. What are the "possible interpretations"? (I am clearly "fishing" here with no idea, really at all, what the nature of the sought function would be, if it even exists in some sense or other.)
Jul 28, 2019 at 17:21 comment added Paul B. Slater Theorem 7 of sciencedirect.com/science/article/pii/0024379594002118 tells us (changing $f$ there to $g$ here) that operator monotone functions $g(t)$ satisfy the relation $g(t)=t g(t^{-1})$--as can be checked with $\frac{1+t}{2}$, and the other examples. (So, maybe I should have set up the whole problem using $g$, not $f$.)
Jul 28, 2019 at 17:18 comment added Pietro Majer Actually it is only clear that you are looking for a function $f$. You should kindly add a definition of its domain, a definition of its co-domain, and a list of properties you want it to have. (Each point in unambiguous way, otherwise the there will be a bunch of possible interpretations!)
Jul 28, 2019 at 17:14 history edited Paul B. Slater CC BY-SA 4.0
second paragraph expanded
Jul 28, 2019 at 17:07 history edited Paul B. Slater CC BY-SA 4.0
f(t) changed to f in title--per comment
Jul 28, 2019 at 17:05 review Close votes
Jul 30, 2019 at 7:42
Jul 28, 2019 at 16:16 comment added Iosif Pinelis It's still unclear what $t$ is. It is not specified in your post by quantifiers "for all" or "there exist(s)" or in any other way.
Jul 28, 2019 at 16:00 comment added Paul B. Slater Per comment of Iosif Pinelis, changed $f(t)$ to $f$ at outset of question. Hopefully, the intent of the question is clear.
Jul 28, 2019 at 15:57 history edited Paul B. Slater CC BY-SA 4.0
deleted 3 characters in body
Jul 28, 2019 at 15:30 comment added Iosif Pinelis What is $t$ in (say) $f(\frac{1+t}{2})=\frac{25}{341}$? Also, what do you mean by "function/functions $f(t)$"? Is $t$ the argument of a function $f$? Then the function is $f$, not $f(t)$.
Jul 28, 2019 at 15:19 history edited Paul B. Slater
edited tags
Jul 28, 2019 at 15:13 history asked Paul B. Slater CC BY-SA 4.0