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Jul 27, 2019 at 13:07 comment added Pietro Majer For compact convex sets, I think Nik Weaver's example is typical, that is for any such sequence $Q_n$ in an infinite dimensional $V$, there exists a subspace $L$ for which the intersection is not continuous. If the $Q_n$ are non-empty, closed, "equi-uniformly convex" sets (hence they are not compact, unless $V$ is finite dimensional), then I guess the continuity of intersection with $L$ is true; maybe also with any closed convex $L$.
Jul 26, 2019 at 16:34 comment added Nik Weaver No problem, you're welcome.
Jul 26, 2019 at 15:28 comment added Steve @NikWeaver That was simpler than expected, thanks!
Jul 26, 2019 at 14:50 comment added Nik Weaver Let $Q$ be the line segment joining $(0,0)$ and $(1,0)$ and let $Q_n$ be the line segment joining $(0,1/n)$ and $(1,0)$.
Jul 26, 2019 at 14:17 comment added Nik Weaver This already fails in $\mathbb{R}^2$.
Jul 26, 2019 at 13:49 history asked Steve CC BY-SA 4.0