Timeline for Replacing the Fibre of a Fibration
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Sep 4, 2023 at 20:08 | comment | added | Dan Ramras | The question raised in my previous comment is addressed here: mathoverflow.net/questions/453933/… | |
| Sep 1, 2023 at 18:06 | comment | added | Dan Ramras | Could someone elaborate on how to produce a fibration over $[0,1]$ with both $F$ and $F'$ as fibers, starting just from a homotopy equivalence $f$ between $F$ and $F'$? The triangle example doesn't seem that informative to me; it suggests that sometimes the mapping cylinder of $f$ will do the trick, but that doesn't work in general (e.g. it fails when $f$ is a constant map from a disk to itself). | |
| Jul 26, 2019 at 10:52 | comment | added | Gael Meigniez | After Peter's comment, I have merged my partial answers. Thanks, Peter. | |
| Jul 26, 2019 at 10:50 | history | edited | Gael Meigniez | CC BY-SA 4.0 |
added 239 characters in body
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| Jul 25, 2019 at 16:10 | comment | added | Connor Malin | Gael, does the projection of a right triangle onto its base not satisfy that? | |
| Jul 20, 2019 at 17:52 | comment | added | Tyrone | Thanks, Gael. If you work out that last step I'd be i'd be interested in seeing it. | |
| Jul 20, 2019 at 17:50 | vote | accept | Tyrone | ||
| S Jul 19, 2019 at 15:00 | history | suggested | Tyrone | CC BY-SA 4.0 |
Edited equations into Mathjax formatting.
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| Jul 19, 2019 at 13:41 | review | Suggested edits | |||
| S Jul 19, 2019 at 15:00 | |||||
| Jul 19, 2019 at 10:03 | history | edited | Gael Meigniez | CC BY-SA 4.0 |
added 354 characters in body
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| Jul 19, 2019 at 9:52 | history | answered | Gael Meigniez | CC BY-SA 4.0 |