Skip to main content
9 events
when toggle format what by license comment
Jul 31, 2019 at 13:47 history closed YCor
Victor Protsak
Derek Holt
Pace Nielsen
LSpice
Not suitable for this site
Jul 19, 2019 at 9:14 comment added Victor Protsak A better generalization is given by finite nilpotent groups. Every finite $p$-group is nilpotent and by a well- known theorem, each finite nilpotent group is isomorphic to the direct product of its Sylow subgroups.
Jul 19, 2019 at 8:57 comment added YCor An example of a reference is Burnside's $p^aq^b$ Theorem (Wikipedia link).
Jul 19, 2019 at 8:25 review Close votes
Jul 31, 2019 at 13:47
Jul 19, 2019 at 8:15 comment added zibadawa timmy Seems unlikely to admit a fairly general approach, because you'd be studying all groups of order $m$ of necessity (as your class would include the groups $G^k$ for any $|G|=m$), and that can get very ad hoc and complex if $m$ isn't very nice. And just about every property that makes $p$-groups study-able in (more-or-less) their entirety are all dependent on the primality. Are there particular things you're hoping to know about such groups?
Jul 19, 2019 at 8:06 history edited YCor CC BY-SA 4.0
added 10 characters in body; edited title
Jul 19, 2019 at 8:05 comment added YCor I guess the right generalization would be to study classes of finite groups in the generated by a group variety under taking extensions. A closer case would be to consider all groups with prime divisors in some given finite set, e.g., all groups of order dividing $6^n$ for some $n$. Indeed the class you're suggesting is not stable under taking subgroups/quotients when $m$ is not a prime power.
Jul 19, 2019 at 6:52 history edited user64494 CC BY-SA 4.0
Typos are corrected.
Jul 19, 2019 at 5:43 history asked Mohammad Radi CC BY-SA 4.0