Timeline for Diophantine equation: $n^2=c(4ab-a-b)-b$?
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
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| May 8, 2021 at 7:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 8, 2021 at 9:02 | comment | added | Wlod AA | @TerryTao, indeed, this $\ 4\!\cdot\! a\!\cdot\! b - a- b\ $ associates immediately with Erdős-Straus. | |
| Jan 8, 2021 at 6:05 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 10, 2020 at 6:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 13, 2020 at 7:18 | comment | added | Dmitry Ezhov | $9k^2=c(4ab-a-b)-b\overset{a\to u+v\\b\to u-v}{\implies}\\ (8 c u - 2 c - 1)^2 - (8 c v - 1)^2 - (2 c + 36 k^2 + 1)^2 + (36 k^2 + 1)^2 = 0 \implies\\(8 c u - 2 c - 1)^2 - (8 c v - 1)^2 - (2 c + 36 k^2 + 1)^2 + (36 k^2 - 1)^2 + (12 k)^2 = 0$ | |
| May 13, 2020 at 6:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 14, 2020 at 6:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 15, 2019 at 5:06 | history | edited | GH from MO |
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| Dec 15, 2019 at 5:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 17, 2019 at 5:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jul 18, 2019 at 4:35 | answer | added | individ | timeline score: 1 | |
| Jul 17, 2019 at 20:08 | comment | added | Terry Tao | The problem looks comparable in difficulty to the Erdos-Straus conjecture en.wikipedia.org/wiki/Erd%C5%91s%E2%80%93Straus_conjecture which remains open (as with this problem, one can handle various congruence classes by explicit algebraic solutions, but these do not cover all cases). | |
| Jul 17, 2019 at 20:01 | history | asked | asad | CC BY-SA 4.0 |