Timeline for Is there some sort of formula for $t(S_n)$?
Current License: CC BY-SA 4.0
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| Jul 14, 2019 at 15:17 | history | edited | Chain Markov | CC BY-SA 4.0 |
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| Jul 14, 2019 at 12:51 | comment | added | Geoff Robinson | The lower bound given in my answer still applies, because the $X$ I chose does generate. | |
| Jul 14, 2019 at 12:45 | comment | added | YCor | Check the references for theorem 3.3 in Breuillard-Lubotzky (ArXiv). It gives something such as $|t(S_n)|\le |S_n|^{1/(1+\delta_n)}$ for some $\delta_n>0$. Of course without stating what is $\delta_n$, this is empty information, but the references are likely to provide you with an explicit value ($\delta_n$ ought to tend to $0$ sufficiently slowly to give an interesting lower bound). | |
| Jul 14, 2019 at 12:37 | comment | added | Chain Markov | @PietroMajer, yes, I meant $t(G)$. $\tau(G)$ was in the previous question... | |
| Jul 14, 2019 at 12:35 | history | edited | Chain Markov | CC BY-SA 4.0 |
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| Jul 14, 2019 at 12:22 | history | asked | Chain Markov | CC BY-SA 4.0 |