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Jul 10, 2019 at 15:52 comment added Fedor Petrov I do not understand how to bypass Laurent.
Jul 10, 2019 at 14:14 comment added Honza Thanks Fedor, a brilliant solution. Is it fair to say that the answer can be built as a sum of $\lambda_j^S$ multiplied by the coefficient of $(1-t*\lambda_j)^{-1}$ in the usual partial-fraction expansion of your F (thus bypassing Laurent - but the same thing I guess)?
Jul 9, 2019 at 22:50 history edited Fedor Petrov CC BY-SA 4.0
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Jul 9, 2019 at 20:11 vote accept Honza
Jul 9, 2019 at 19:09 history answered Fedor Petrov CC BY-SA 4.0