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Jul 12, 2019 at 21:11 history closed Jan-Christoph Schlage-Puchta
YCor
Pace Nielsen
user44191
Dima Pasechnik
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Jul 8, 2019 at 12:01 comment added YCor This is not what's usually called "uniformly continuous". In this precise setting (functions from $\mathbf{Z}^k$ to any metric space), this is just "Lipschitz". In the usual definition, every function from a uniformly discrete metric space to any metric space is uniformly continuous.
Jul 8, 2019 at 8:50 review Close votes
Jul 12, 2019 at 21:11
Jul 8, 2019 at 8:08 vote accept Dominic van der Zypen
Jul 8, 2019 at 7:57 answer added Fedor Petrov timeline score: 14
Jul 8, 2019 at 7:48 history asked Dominic van der Zypen CC BY-SA 4.0