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Jul 8, 2019 at 2:36 comment added joaopa Sorry my queston is not relevant. I have difficulties with embeddings.
Jul 5, 2019 at 14:55 comment added Felipe Voloch $\deg(x)$ is not well defined the way you suggest. $K$ may have several different embeddings into $\Omega$. You may want to define $\deg(x) = [K:\mathbb{F}_q(x)]$ but that's a different question.
Jul 4, 2019 at 13:01 comment added joaopa I use it through $\deg$.
Jul 4, 2019 at 0:52 comment added LSpice I just meant that, after defining $\Omega$, it seems that you do not use it again.
Jul 4, 2019 at 0:35 history edited joaopa CC BY-SA 4.0
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Jul 4, 2019 at 0:28 comment added joaopa $\Omega$ is where the $-\deg$ valuation lives. I could have taken only an algebraic closure of $\mathbb F_q(\left(\left(\frac 1T\right)\right)$ if you prefer.
Jul 4, 2019 at 0:03 comment added LSpice What is the rôle of $\Omega$ in your question?
Jul 3, 2019 at 23:37 history asked joaopa CC BY-SA 4.0