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Jul 3, 2019 at 13:32 vote accept Hexhist
Jul 2, 2019 at 21:17 comment added Daniel Litt And I think that over an algebraically closed field, this should be true for any linear algebraic group whatsoever (since the unipotent radical is also in the ring, and is special.)
Jul 2, 2019 at 20:37 history answered Victor Petrov CC BY-SA 4.0