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Jul 3, 2019 at 16:25 comment added Slava Rychkov It's Example II.15, not 11.15
Jul 1, 2019 at 18:13 vote accept Aidan Rocke
Jul 1, 2019 at 16:04 history edited Aidan Rocke
there is a strong connection here to random graphs
Jun 30, 2019 at 13:33 history edited Aidan Rocke CC BY-SA 4.0
clarified my hypothesis
Jun 30, 2019 at 8:21 history edited Aidan Rocke CC BY-SA 4.0
improved question title
Jun 30, 2019 at 5:37 comment added Gerry Myerson Number of connected labeled graphs with n nodes is tabulated, with many links and references, at oeis.org/A001187
Jun 30, 2019 at 0:37 answer added Aidan Rocke timeline score: 1
Jun 27, 2019 at 17:42 comment added Richard Stanley According to Example 11.15 in Flajolet and Sedgewick, Analytic Combinatorics, the number $K_n$ of labeled connected graphs on $n$ vertices satisfies $K_n=2^{{n\choose 2}}(1-2n2^{-n}+o(2^{-n}))$.
Jun 27, 2019 at 16:27 history asked Aidan Rocke CC BY-SA 4.0