Skip to main content

Timeline for Generalization of normal subgroup

Current License: CC BY-SA 4.0

5 events
when toggle format what by license comment
Jun 25, 2019 at 13:30 review Close votes
Jun 28, 2019 at 16:29
Jun 25, 2019 at 8:34 comment added Geoff Robinson If $A,B$ are subgroups, then we always have $[A,B] \lhd \langle A,B \rangle, $ so the conclusion that the commutator is normal in the intersection for a "normal pair" does not seem very strong.Your subgroups are just mutually normalizing, as Dirk says, which is a situation often encountered and well-studied.
Jun 25, 2019 at 8:16 comment added YCor As mentioned, it's the combination of two properties which each are easily formulated using standard group theory language. I guess that "normal pair" could be misleading (a normal thing usually means something invariant under conjugation).
Jun 25, 2019 at 7:19 comment added Dirk If I'm not mistaken, your property is equivalent to $A \subseteq N_G(B)$ and $B \subseteq N_G(A)$, where $N_G(\cdot)$ denotes the normalizer. Maybe this is already discussed somewhere?
Jun 25, 2019 at 6:55 history asked pre-kidney CC BY-SA 4.0