Timeline for Uniqueness of l1 minimization
Current License: CC BY-SA 4.0
15 events
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| Jun 26, 2019 at 11:28 | comment | added | love_backups | Could you please elaborate on your answer? Specifically, I do not see the link between what I have written in the question and what is written on the page 75 in the Foucart's talk. | |
| Jun 25, 2019 at 21:20 | history | edited | Josiah Park | CC BY-SA 4.0 |
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| Jun 25, 2019 at 21:20 | comment | added | Josiah Park | @love_backups It should be $\|\cdot\|_{\infty}$ above. This has been updated. | |
| Jun 25, 2019 at 16:40 | comment | added | love_backups | Isn't it $||D^Tx||_1 \leq \sum\limits_{i = 1}^n ||d_i^T x||_\infty ||x||_1 \leq n \max|d_{ij}| ||x||_1$. That is, we cannot bound by $\max |(I - QA)|_{j,k}$ alone. Or are you using some kind of generalized H\"olders inequality? | |
| Jun 25, 2019 at 15:22 | comment | added | love_backups | I don't see how to relate $||I - QA||_\infty$ and $\max \limits_{x \in \mathbb{R}^n}||x - QAx||_1$. | |
| Jun 25, 2019 at 13:04 | vote | accept | love_backups | ||
| Jun 25, 2019 at 13:03 | vote | accept | love_backups | ||
| Jun 25, 2019 at 13:04 | |||||
| Jun 24, 2019 at 19:22 | history | edited | Josiah Park | CC BY-SA 4.0 |
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| Jun 24, 2019 at 19:16 | history | edited | Josiah Park | CC BY-SA 4.0 |
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| Jun 24, 2019 at 19:10 | history | edited | Josiah Park | CC BY-SA 4.0 |
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| Jun 24, 2019 at 19:10 | review | Low quality posts | |||
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| Jun 24, 2019 at 19:07 | history | undeleted | Josiah Park | ||
| Jun 24, 2019 at 18:35 | history | edited | Josiah Park | CC BY-SA 4.0 |
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| Jun 24, 2019 at 18:34 | history | deleted | Josiah Park | via Vote | |
| Jun 24, 2019 at 18:29 | history | answered | Josiah Park | CC BY-SA 4.0 |