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Jun 23, 2019 at 7:31 comment added Andrea Marino Yes! You are right. Both are fully faithful!
Jun 23, 2019 at 1:42 comment added Todd Trimble Thanks! The colimit in the second case is also known as a Prüfer group: en.wikipedia.org/wiki/Pr%C3%BCfer_group. The only thing I'd add to your proof is that the inclusion $Grp \to sSet$ is fully faithful, so that if the colimits on the simplicial set side were isomorphic, they'd have to be isomorphic on the group side, leading to a contradiction as you explained.
Jun 23, 2019 at 0:52 history answered Andrea Marino CC BY-SA 4.0