Timeline for "half arithmetic progressions" in dense sets
Current License: CC BY-SA 2.5
2 events
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| Oct 29, 2009 at 22:28 | comment | added | Mark Lewko | Crystal, thanks for your comments. My question wasn't very clear (I've attempted to update it). I intended for it to be permissible for the half of S that does not intersect A to lie in [1,N]. For example, if A=[4/10N, 5/10N] it is valid to take S = [3/10N,5/10N] to produce a half AP of length 2/10N. | |
| Oct 29, 2009 at 21:49 | history | answered | Kristal Cantwell | CC BY-SA 2.5 |