Timeline for Explicit formula for Euler zigzag numbers(Up/down numbers)
Current License: CC BY-SA 2.5
7 events
| when toggle format | what | by | license | comment | |
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| Jul 4, 2016 at 7:36 | comment | added | Todd Trimble | Wadim, can you check out the last comment? Also, I'm not able to find your claimed formula under oeis.org/A000111 Thanks. | |
| Jul 4, 2016 at 7:06 | comment | added | user94635 | $$ A_m=2^m\biggl|E_m\biggl(\frac12\biggr)+E_m(1)\biggr| $$ In this case, $A_0 =2^0\biggl|1+1\biggr|=2≠1$, Is there wrong with my arithmetic? | |
| Jul 27, 2010 at 23:46 | comment | added | Wadim Zudilin | Ross, who care about having another formula for the same sequence if this is just a new formula without applications or with applications which can be achieved by a known one?! | |
| Jul 27, 2010 at 14:00 | comment | added | Ross Tang | Wadim, you are right. It is really an explicit formula. I didn't notice it since I don't know Euler polynomials has explicit expansion. However, the formula you provided has an absolute sign. I think it will make all the manipulation and computation inconvenient? | |
| Jul 27, 2010 at 8:54 | history | edited | Wadim Zudilin | CC BY-SA 2.5 |
a tiny misprint corrected
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| Jul 27, 2010 at 0:11 | history | edited | Will Jagy | CC BY-SA 2.5 |
Toss to Ross, correct unless known nickname
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| Jul 26, 2010 at 23:35 | history | answered | Wadim Zudilin | CC BY-SA 2.5 |