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when toggle format what by license comment
Jun 20, 2019 at 8:29 comment added Ben McKay Yes, you left translate the charts around.
Jun 20, 2019 at 8:23 comment added Bey Alexander correct me if i'm wrong so if any point $g\in mathcal{G}$ taking chart of identity in $mathcal{G}^{*}$, $(U,\phi)$, then $(g.U,\phi(g^{-1}))$ can considered as chart of $g$ in $mathcal{G}$.
Jun 20, 2019 at 8:18 vote accept Bey Alexander
Jun 20, 2019 at 6:27 history answered Ben McKay CC BY-SA 4.0