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Jun 29, 2021 at 20:54 history edited ofer zeitouni CC BY-SA 4.0
fixed typo
Jun 29, 2021 at 11:48 comment added dohmatob @oferzeitouni Possible typo: $m=\alpha_d s$ ==> $m=\alpha_d d$.
Jun 17, 2019 at 20:22 comment added ofer zeitouni and the normalization is as in the wikipedia page I quoted. You get $1/d$ from the empirical measure and $1/m^2$ from the normalization of the entries (you are taking the square of the MP matrix...)
Jun 17, 2019 at 20:19 comment added ofer zeitouni That is the limiting case, in which the limit empirical measure is a dirac at 1....
Jun 17, 2019 at 20:19 comment added hookah And also why the normalization is by $d^{-1}m^{-2}$? I understand that MP law requires $\frac1m$ normalization, and you get an extra for $d$, but why $d^2$?
Jun 17, 2019 at 20:13 vote accept hookah
Jun 17, 2019 at 20:13 comment added hookah Ofer, thanks for the answer. Sorry, if it is a trivial question: How to handle the case $\alpha\to+\infty$ (more precisely, when $d\to+\infty$ and $d=o(m)$)?
Jun 17, 2019 at 19:53 history answered ofer zeitouni CC BY-SA 4.0