Timeline for Why are two notions of Gaussian curvature are the same - what is the simplest & most didactic proof?
Current License: CC BY-SA 3.0
25 events
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Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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S Jul 10, 2015 at 14:42 | history | suggested | Tim | CC BY-SA 3.0 |
chatter in title
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Jul 10, 2015 at 13:54 | review | Suggested edits | |||
S Jul 10, 2015 at 14:42 | |||||
Aug 16, 2013 at 3:02 | comment | added | Włodzimierz Holsztyński | I feel that this extra "[STILL OPEN]" is an offensive eyesore. Does it really buy anything? (It shouldn't). | |
Aug 15, 2013 at 15:53 | answer | added | Anton Petrunin | timeline score: 5 | |
Mar 3, 2011 at 14:25 | comment | added | Steven Gubkin | @Victor - I think the point is that some people who come to MO just to answer questions might see the dark green box next to this one and pass it by without a glance. I myself do not treat MO this way, but I guess some people might. For attracting such people the [Still Open] is needed. | |
Mar 3, 2011 at 12:38 | answer | added | Diego Matessi | timeline score: 5 | |
Aug 5, 2010 at 19:23 | comment | added | Victor Protsak | I think that you've already explained it well in the opening paragraph (in bold, so hard to miss). If a person has something to contribute (and doesn't care about MO formalities), experience suggests that (s)he would do it no matter what. For the others, it's a visual annoyance and may be interpreted as an unfair way to attract attention. | |
Aug 5, 2010 at 18:49 | comment | added | Ilya Grigoriev | @Victor: What do you mean it's not accurate? The reason I put it there is that I don't want people to think that this question is answered even though it has an accepted answer, is colored accordingly in lists, etc. How else should I communicate this information? | |
Aug 5, 2010 at 2:22 | comment | added | Victor Protsak | I agree that it's an interesting question, but as a courtesy to fellow MOers, can you, please, remove [STILL OPEN] from the title? This is visual spam and not particularly accurate, as you explain in the opening paragraph. | |
Aug 4, 2010 at 17:56 | history | edited | Ilya Grigoriev | CC BY-SA 2.5 |
deleted 27 characters in body
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Aug 4, 2010 at 17:54 | vote | accept | Ilya Grigoriev | ||
Aug 4, 2010 at 17:54 | history | bounty ended | Ilya Grigoriev | ||
Aug 3, 2010 at 23:06 | history | edited | Ilya Grigoriev | CC BY-SA 2.5 |
added 331 characters in body; edited title
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Aug 1, 2010 at 22:44 | answer | added | Andrey Rekalo | timeline score: 6 | |
Jul 30, 2010 at 5:06 | answer | added | Dan Lee | timeline score: 0 | |
Jul 29, 2010 at 18:49 | answer | added | S. Carnahan♦ | timeline score: 4 | |
Jul 28, 2010 at 23:33 | history | bounty started | Ilya Grigoriev | ||
Jul 27, 2010 at 21:51 | comment | added | Victor Protsak | I taught Gauss-Bonnet theorem in one class following the book of Rashevskii (in Russian; you can find a copy on the I-net). His geometric explanation using parallel transport is very good, but maybe it's more than one can reasonably hope to impart in a 5-day course. By GB I mean the version with a closed piecewise-smooth contour, $$\iint Kd\sigma +\int \kappa_g ds +\sum\Delta \psi = 2\pi.$$ | |
Jul 27, 2010 at 14:33 | answer | added | Vaughn Climenhaga | timeline score: 1 | |
Jul 27, 2010 at 13:46 | comment | added | Andrey Rekalo | Marcel Berger gives an illuminating presentation of the Theorema Egregium and discusses the connection of the Gauss-Bonnet formula with parallel transport in ["A panoramic view of Riemannian geometry"][1]. [1]: books.google.co.uk/… | |
Jul 27, 2010 at 13:37 | answer | added | Deane Yang | timeline score: 2 | |
Jul 27, 2010 at 12:31 | history | edited | Ilya Grigoriev | CC BY-SA 2.5 |
added 318 characters in body; added 26 characters in body
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Jul 26, 2010 at 15:08 | history | edited | Ilya Grigoriev | CC BY-SA 2.5 |
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Jul 26, 2010 at 14:57 | history | asked | Ilya Grigoriev | CC BY-SA 2.5 |