Timeline for Explicit formula for Euler zigzag numbers(Up/down numbers)
Current License: CC BY-SA 2.5
14 events
when toggle format | what | by | license | comment | |
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Jul 3, 2016 at 12:10 | comment | added | Todd Trimble | It says "Your website is not available" when I click on the second and third links. | |
Jul 27, 2010 at 11:48 | comment | added | Ross Tang | Dear everyone, I found the above formula when I am trying to solve a partial difference equation as an exercise. mathoverflow.net/questions/33498/… The Euler zigzag numbers are secant and tangent number respectively for the even term and odd term, and it is given by $A_0^n$ from the sequence $A_k^n$ from the above link. I would be very please if anyone can give me some insight in solving the partial difference equation. Thank you. | |
Jul 26, 2010 at 23:35 | answer | added | Wadim Zudilin | timeline score: 2 | |
Jul 26, 2010 at 15:51 | history | edited | Robin Chapman | CC BY-SA 2.5 |
Tex made display
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Jul 26, 2010 at 15:37 | history | edited | Ross Tang | CC BY-SA 2.5 |
added 90 characters in body
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Jul 26, 2010 at 15:23 | history | edited | Ross Tang | CC BY-SA 2.5 |
added 12 characters in body
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Jul 26, 2010 at 15:18 | comment | added | Ross Tang | @Wadim Zudilin: At which session do u refer to? I found none explicit formula in the Formula session. Thank you for your reference. | |
Jul 26, 2010 at 12:50 | comment | added | Pietro Majer | I by no means want to diminish your result, but I'd say it could be new, or known, or already discovered and forgotten several times. Is 8837*93934=830094758 a new result or not? | |
Jul 26, 2010 at 12:45 | comment | added | Wadim Zudilin | @JBL: $i=\sqrt{-1}$ :-) | |
Jul 26, 2010 at 12:45 | comment | added | Wadim Zudilin | Your formula is too tiny to be really new! :-) Jokes aside, the wolframworld page gives the link to OEIS, research.att.com/~njas/sequences/A000111, from which I see many compact explicit formulas for your (and Euler's, of course) numbers. | |
Jul 26, 2010 at 12:39 | comment | added | JBL | Also, what is $i$? | |
Jul 26, 2010 at 12:38 | comment | added | JBL | Could you please put your formula in display mode so that it is legible? Also, \binom{n}{k} is a much nicer binomial coefficient. | |
Jul 26, 2010 at 12:37 | history | edited | JBL |
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Jul 26, 2010 at 12:22 | history | asked | Ross Tang | CC BY-SA 2.5 |