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Sep 5 at 7:54 history edited Pedja CC BY-SA 4.0
New formulation of criterion
Jul 12, 2019 at 3:50 comment added Pedja @MaxAlekseyev No, it isn't. In post you mentioned we treat numbers of the form $N =k \cdot b^n-1$ with base $b$ being an even number not divisible by $3$ .
Jul 11, 2019 at 20:20 comment added Max Alekseyev Is this a partial case of mathoverflow.net/q/308886 ?
Jun 12, 2019 at 14:04 history asked Pedja CC BY-SA 4.0