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Jun 12, 2019 at 6:15 comment added naf Let $K$ be a finite Galois extension over which the group scheme $G$ splits. Then $G_K$ acts on $A_K := A \otimes_k K$ and $Gal(K/k)$ also acts on $A_K$ via its action on $K$. What you need to show is that the action of $Gal(K/k)$ preserves $(A_K)^{G_K}$; the invariants of this action will then give the quotient over $k$ that you want.
Jun 11, 2019 at 12:55 review Close votes
Jun 16, 2019 at 3:05
Jun 11, 2019 at 11:34 comment added Gaussian @ulrich: I am still getting familiar with it. Could you please make a more detailed answer? This would be very helpful! :)
Jun 11, 2019 at 11:32 comment added LSpice A minor TeX point: you want $\mathrm{Spec}(A)$ \mathrm{Spec}(A) or ${\rm Spec}(A)$ {\rm Spec}(A), not $\rm{Spec}(A)$ \rm{Spec}(A). Even better is $\operatorname{Spec}(A)$ \operatorname{Spec}(A). I have edited accordingly.
Jun 11, 2019 at 11:31 history edited LSpice CC BY-SA 4.0
TeX fixes
Jun 11, 2019 at 10:34 comment added naf If you are comfortable with descent, then you can take the quotient over a finite Galois extension of $k$ over which the group splits and then show that it has descent data with respect to the field extension.
Jun 11, 2019 at 10:24 history asked Gaussian CC BY-SA 4.0