Timeline for Maximum conjugacy class size in $S_n$ with fixed number of cycles
Current License: CC BY-SA 4.0
4 events
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| Jun 11, 2019 at 9:27 | history | edited | Gerhard Paseman | CC BY-SA 4.0 |
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| Jun 11, 2019 at 2:30 | comment | added | Gerhard Paseman | In addition to adding to the largest cycle, we can also borrow. Suppose we have m-1 fixed points and n sufficiently large (n > 3m, maybe?). Then for d with (d!)*2^d less than m-1, we can build d many 2 cycles and borrow from the largest cycle and still reduce the denominator. We can similarly craft a few small cycles from an equal number of 1 and 2 cycles and some borrowing from the largest cycle. Gerhard "Optimizing Is Give And Take" Paseman, 2019.06.10. | |
| Jun 11, 2019 at 2:14 | history | edited | Gerhard Paseman | CC BY-SA 4.0 |
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| Jun 11, 2019 at 1:58 | history | answered | Gerhard Paseman | CC BY-SA 4.0 |