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Jun 8, 2019 at 6:18 comment added Lwins @AnthonyQuas Well, I once wanted to delete this question when Iosif pointed out the answer because that made me feel myself so stupid. :P
Jun 8, 2019 at 6:15 comment added Anthony Quas Sorry. I had read it as taking values in $[-1,1]$, not ${-1,1}$.
Jun 8, 2019 at 6:06 comment added Lwins @AnthonyQuas Note how we determine the r.v. $x$. It will always perpendicular to either $\alpha_1$ or $alpha_2$.
Jun 8, 2019 at 3:53 comment added Anthony Quas I’m missing something here. If you take your $\alpha_1$ and $\alpha_2$, why is the expectation zero? It seems that you’re taking a product of non-negative numbers, and the product is only zero if $x$ is perpendicular to one of the $\alpha$’s, so the product is almost surely positive, and the expectation is positive.
Jun 7, 2019 at 4:14 history edited user64494 CC BY-SA 4.0
The title is improved.
Jun 6, 2019 at 18:33 vote accept Lwins
Jun 6, 2019 at 18:23 answer added Iosif Pinelis timeline score: 3
Jun 6, 2019 at 14:39 history edited Lwins CC BY-SA 4.0
added 323 characters in body
Jun 6, 2019 at 14:30 history asked Lwins CC BY-SA 4.0