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Jun 15, 2019 at 5:52 comment added abx @Jérémy Blanc: Oops, of course, thanks. I guess I got confused with the degree of the branch locus.
Jun 14, 2019 at 19:31 comment added Jérémy Blanc @abx I think you mean del Pezzo surface of degree $2$, not $4$.
Jun 5, 2019 at 15:49 comment added Sheng Meng @abx Thanks for the precise example! Indeed, any projective variety of dimension $n$ has a finite surjective morphism to $\mathbb{P}^n$.
Jun 5, 2019 at 14:30 review Close votes
Jun 11, 2019 at 3:05
Jun 5, 2019 at 14:13 comment added abx Take $Y=\mathbb{P}^2$, $X=$ a del Pezzo surface of degree 4. There is a double covering $\pi : X\rightarrow \mathbb{P}^2$ and a birational morphism $\tau :X\rightarrow \Bbb{P}^2$ obtained by blowing up 7 points in general position.
Jun 5, 2019 at 11:25 comment added Sheng Meng @NickL The original question has many other assumptions, I just wonder what happens if removing all the assumptions. I would appreciate you copy this comment to an answer, I guess you mean $X:=$ blowup of $\mathbb{P}^2$, right? It has finite morphism to $\mathbb{P}^2$.
Jun 5, 2019 at 11:15 comment added Sheng Meng @NickL If $\pi$ is isomorphic, then $\tau:X\to Y\cong X$ is a birational automorphism which has to be an automorphism.
Jun 5, 2019 at 11:03 comment added Sheng Meng @NickL Thanks, I see!
Jun 5, 2019 at 10:59 comment added Nick L The blow down of a $(-1)$-curve is a counter example. Maybe there is an error in the question, because the statement in brackets doesn't make sense i.e. there is no relation between $\pi$ and $\tau$.
Jun 5, 2019 at 10:54 history asked Sheng Meng CC BY-SA 4.0