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Jun 4, 2019 at 14:49 answer added Piotr Hajlasz timeline score: 3
Jun 4, 2019 at 14:32 comment added Daniele Tampieri I am not sure on how to proceed, but intuitively I would try to show that $u\in BV$ (or $BV_\mathrm{loc}$) implies $u$ is essentially bounded, i.e. $u\in L^\infty_\mathrm{loc}$: then I would show that seestial bondedness imply a control of the (essential) oscillation in terms of the $BV$ norm. I do not post a full answer since I am not yet skilled enough to work quickly with the extension of those concepts in dimension $N>1$.
Jun 4, 2019 at 14:14 comment added user140746 @DanieleTampieri Thank you. How would the proof go in the general case?
Jun 4, 2019 at 12:45 comment added Daniele Tampieri When $N=1$ and you use the classical definition of total variation $$V^a_b(f)=\sup_{\mathcal{P}} \sum_{i=0}^{n_P-1} | f(x_{i+1})-f(x_i) |$$ where $\mathcal{P} =\left\{P=\{ x_0, \dots , x_{n_P}\}|P\text{ is a partition of } [a,b] \right\}$, then this is certainly true since $u$ is bounded. In the case $N>1$ you should recur to a concept of essential (in the sense of measure theory) oscillation.
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Jun 4, 2019 at 12:27
Jun 4, 2019 at 11:25 history asked user140746 CC BY-SA 4.0