Timeline for Closest points of curves on convex surfaces
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 5, 2019 at 10:01 | vote | accept | Jiří Minarčík | ||
| Jun 3, 2019 at 16:31 | answer | added | Jiří Minarčík | timeline score: 0 | |
| Jun 3, 2019 at 16:04 | comment | added | fedja | Replace straight lines by circles of sufficiently big radii. The effect will be the same. Qualitative assumptions ($>0$ without explicit bounds) are usually useless in such matters... | |
| Jun 3, 2019 at 13:45 | comment | added | Jiří Minarčík | @PietroMajer Thank you for the observation. You understand the statement correctly. I added an additional assumption on the surface $\Sigma$ to reflect your comment. | |
| Jun 3, 2019 at 13:41 | history | edited | Jiří Minarčík | CC BY-SA 4.0 |
Added an additional assumption on the surface $\Sigma$ to reflect the observation by Pietro Majer.
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| Jun 3, 2019 at 12:48 | comment | added | Pietro Majer | I'm not sure I got the statement: Suppose $\Sigma$ contains two flat parallel areas, e.g the unit disk on the x,y plane centred on the origin $O:=(0,0,0)$, and its translate by $(0,0,1),$ centred at $P:=(0,0,1)$. Suppose $\gamma$ has a straight segment passing for the origin, say $\gamma(u_1)=O$ and another straight segment passing for $P$, say $\gamma(u_2)=P$. This gives a local minimum of $\phi$ in $(u_1,u_2)$, with non collinear tangent vectors. | |
| Jun 3, 2019 at 12:46 | history | edited | Jiří Minarčík |
edited tags
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| Jun 3, 2019 at 9:44 | history | asked | Jiří Minarčík | CC BY-SA 4.0 |