Timeline for Sub-Gaussian decay of convolution of $L^1$ function with Gaussian kernel
Current License: CC BY-SA 4.0
5 events
when toggle format | what | by | license | comment | |
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Jun 3, 2019 at 15:29 | history | bounty ended | neverevernever | ||
Jun 3, 2019 at 7:43 | comment | added | Yuval Peres | This is just the power of proof by contradiction- If your conclusion did not hold, then the convolutions $f*1_{B_1}$ and $f*g$ would be comparable, but the first is completely local while the second takes into account neighboring values, so for them to have bounded ratio implies that the decay can be no faster than exponential. | |
Jun 3, 2019 at 1:38 | comment | added | neverevernever | Thank you! This is such a brilliant answer! Is there any clue on how you come up with this proof? Or this is just so trivial or standard for you ... And the system tells me that I can only give you the 50 points 12 hours later and I will do it then! | |
Jun 3, 2019 at 1:34 | vote | accept | neverevernever | ||
Jun 3, 2019 at 1:04 | history | answered | Yuval Peres | CC BY-SA 4.0 |