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when toggle format what by license comment
Jun 4, 2019 at 7:16 comment added user85365 Yes, this solves the problem for $(X^{\mathbb{Z}},D_1)$, and consequently also for $(X^{\mathbb{Z}},D_2)$! Thank you!
Jun 2, 2019 at 13:47 history answered Niels J. Diepeveen CC BY-SA 4.0